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          	<article class='markdown-body'>
            	<h1 id="11-">11. 旋转数组的最小数字</h1>
<p>难度 <strong>简单</strong></p>
<p>把一个数组最开始的若干个元素搬到数组的末尾，我们称之为数组的旋转。输入一个递增排序的数组的一个旋转，输出旋转数组的最小元素。例如，数组 <code>[3,4,5,1,2]</code> 为 <code>[1,2,3,4,5]</code> 的一个旋转，该数组的最小值为1。 </p>
<p><strong>示例 1：</strong></p>
<pre><code>输入：[3,4,5,1,2]
输出：1
</code></pre><p><strong>示例 2：</strong></p>
<pre><code>输入：[2,2,2,0,1]
输出：0
</code></pre><hr>
<p>思路：二分法，mid 和 right 比较 ，</p>
<ul>
<li>如果 mid 上的值大，则说明最小值在<strong>右</strong>边；</li>
<li>如果 right 上的值大，则说明最小值在<strong>左</strong>边；</li>
<li>如果 mid 上的值等于 right上的，则无法确定，让right--，进行新的一轮循环</li>
</ul>
<pre><code class="lang-java">
class Solution {
    public int minArray(int[] numbers) {
        if(numbers.length == 0){
            return 0;
        }
        if(numbers.length == 1){
            return numbers[0];
        }
        int l = 0;
        int r = numbers.length - 1;
        int mid;
        while(l &lt; r){
            mid = l + ((r - l) &gt;&gt; 1);
            if(numbers[mid] &lt; numbers[r]){
                r = mid;
            }else if(numbers[mid] &gt; numbers[r]){
                l = mid + 1;
            }else{
                r--;
            }
        }
        return numbers[l];
    }

}
</code></pre>

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